rotate polar angle by an arbitrary angle

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Jingtao
Jingtao am 10 Jun. 2023
Kommentiert: Jingtao am 10 Jun. 2023
I got a polar angle map THETA0 from running the snippet below.
N = 1024;
x0 = linspace(-N/2, N/2, N);
y0 = x0;
[X0,Y0] = meshgrid(x0,y0);
[THETA0,R0] = cart2pol(X0,Y0);
But cart2pol returns polar angle map starting from the positive x-axis. I want to get a polar angle map starting at an arbitrary angle of beta. How can I realize this?

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Matt J
Matt J am 10 Jun. 2023
THETA0=THETA0-beta;
  1 Kommentar
Jingtao
Jingtao am 10 Jun. 2023
Thanks! THETA0=mod(THETA0-beta,2*pi) works right!

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