Filter löschen
Filter löschen

Why doesn't it work? - Different size between Left side and Right side

6 Ansichten (letzte 30 Tage)
성우
성우 am 4 Jun. 2023
Kommentiert: 성우 am 4 Jun. 2023
% 변수 정의
m = [1100, 200, 70, 17, 7, 1624]; % 질량
k = [25, 400, 6, 330, 290, 25]; % 강성
% 감쇠 계수
alpha = 0.01;
beta = 0.01;
% 초기 조건
x0 = [0; 0; 0; 0; 0; 0]; % 초기 변위 (0으로 설정)
v0 = [10; 10; 10; 10; 10; 10]; % 초기 속도 (10m/s로 설정)
% 감쇠 행렬
C = alpha * diag(m) + beta * diag(k);
% 강제진동 방정식의 특수해 함수
F = @(t) sin(2*pi*10*t); % 예시로 sin(2*pi*10*t) 가진력 사용
% 시간 범위 정의
t = 0:0.001:10; % 0부터 10까지 0.1 단위로 증가하는 시간 벡터
% 모드감쇠 비례감쇠 계수
zeta = [alpha/m(1), alpha/m(2), alpha/m(3), alpha/m(4), alpha/m(5), alpha/m(6)];
% 모드합성법을 위한 모드해 계산
[V, D] = eig(k - 1i*C);
% 각 모드해의 고유진동수와 진동형상 계산
omega = sqrt(diag(D));
phi = V;
% 중첩된 모드해들의 합을 위한 초기화
x_p = zeros(size(phi, 2), length(t));
for i = 1:length(t)
for j = 1:size(phi, 2)
x_p(j, i) = phi(:, j)' * F(t(i)) / ((omega(j)^2) - (2*zeta(j)*omega(j)*1i) - (omega(j)^2));
end
end
% 전체 해 계산 (중첩된 모드해들의 합)
x = real(phi * x_p.' + exp(-zeta(1)*omega(1)*t) * (phi(:, 1)'*x0 + phi(:, 1)'*v0/(omega(1)*sqrt(1 - zeta(1)^2))));
% 결과 그래프 출력
figure;
plot(t, x); % 시간 응답 그래프 출력
xlabel('Time');
ylabel('Displacement');
title('Response of the system');
% At the 37th line, They don't work

Antworten (2)

KALYAN ACHARJYA
KALYAN ACHARJYA am 4 Jun. 2023
phi(:, j)' * F(t(i)) / ((omega(j)^2) - (2*zeta(j)*omega(j)*1i) - (omega(j)^2));
The result of the above statement is vector, not scalar (single digit), example
>> phi(:, j)' * F(t(i)) / ((omega(j)^2) - (2*zeta(j)*omega(j)*1i) - (omega(j)^2))
ans =
1.0e-10 *
0.0269 - 0.0270i 0.0773 - 0.0774i -0.0894 + 0.0895i 0.7741 - 0.7753i -0.9901 + 0.9901i 0.0163 - 0.0163i
To store vector data, you need to consider the cell array instead of the normal array, please see the description of the cell array here with curly bracket { }
The later step of the code will change, if you consider working with a cell array (specifically *operation).
x_p = cell(size(phi, 2), length(t));
for i = 1:length(t)
for j = 1:size(phi, 2)
disp('kalyan')
x_p{j, i} = phi(:, j)' * F(t(i)) / ((omega(j)^2) - (2*zeta(j)*omega(j)*1i) - (omega(j)^2));
end
Hope it helps!

Atsushi Ueno
Atsushi Ueno am 4 Jun. 2023
It's just like below.
a = 0;
a(1,1) = [1 2 3 4 5 6]
Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-6.
You should make left-hand variable to ...
  • 3 dimension array
  • cell array
  • other type like struct

Kategorien

Mehr zu Genomics and Next Generation Sequencing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by