three order complex coefficient polynomial root matlab
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hi, I would like to find the root for a 3rd order polynomial with complex coefficient.
The polynomial is like:
28x^3 + Ax^2 + Bx - C = 0;
A,B,C are complex numbers.
I appreciate if anyone can help.
0 Kommentare
Antworten (3)
Star Strider
am 26 Mai 2023
There are at least two options —
z = complex(randn(3,1), randn(3,1))
r = roots([28; z])
syms x
p = 28*x.^3 + z(1,:)*x.^2 + z(2,:)*x + z(3,:);
vpap = vpa(p, 5)
r = vpa(solve(p), 5)
.
0 Kommentare
John D'Errico
am 26 Mai 2023
Another classic solution is to find the matrix that has the same eigenvalues as your polynomial has roots. Then use eig to compute the eigenvalues of this "companion matrix". This is in fact what roots does.
0 Kommentare
Walter Roberson
am 26 Mai 2023
syms x A B C
eqn = 28*x^3 + A*x^2 + B*x - C == 0;
solutions = solve(eqn, x, 'MaxDegree', 3)
char(solutions(1))
char(solutions(2))
char(solutions(3))
0 Kommentare
Siehe auch
Kategorien
Mehr zu Polynomials finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!