how can i get the graph of this iterative sequence
t=@(n)(1/(n+2)^2);r=1/5;
g=@(x)((x-1)/(exp(x)));
tolerance=0.000001;
k=100;
x=zeros(1,k);
x(1)=0.3977;
for n=1:k
x(n+1)=(1-(r)*g(x(n)))*(1-t(n))*x(n);
if abs(x(n+1)-x(n))<tolerance
fprintf('The sequence converges after %d iterations for tolerance = %f', n, tolerance)
break;
end
end
x=x(1:n+1); %discard the zeros
format long
disp(x)

 Akzeptierte Antwort

Torsten
Torsten am 20 Mai 2023
Bearbeitet: Torsten am 20 Mai 2023

0 Stimmen

Add the command
plot(1:n+1,x)
at the end of your code.

2 Kommentare

Basha
Basha am 21 Mai 2023
is it possible to dispaly more than one graph by changing x(1)?
t=@(n)(1/(n+2)^2);r=1/5;
g=@(x)((x-1)/(exp(x)));
tolerance=0.000001;
k=100;
N=20;
hold on
for NN=1:N
x(1)=rand;
for n=1:k
x(n+1)=(1-(r)*g(x(n)))*(1-t(n))*x(n);
if abs(x(n+1)-x(n))<tolerance
fprintf('The sequence converges after %d iterations for tolerance = %f', n, tolerance)
break;
end
end
plot(1:n+1,x)
end
hold off
grid on

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R2023a

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Gefragt:

am 20 Mai 2023

Kommentiert:

am 21 Mai 2023

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