Solving a complicated system of ODEs

I'm trying to numerically solve a set of differential equations by using ode45 (I don't know if this is the most appropriate one). My code is below. The annoying thing is that this seems to run but gives invalid solutions. Also, the k parameter should be a variable, not a parameter with a specific value. I don't know how to implement this. It is certainly possible that my initial conditions are incorrect, however, this shouldn't really have an impact if the code runs or not I think.
I'm not fluent at all with this syntax, so bare with me for not understanding everything.
EDIT: I've added the problem I am solving below. Note that the transfer function depends on k and can be obtained through δ I believe. I'll have to check this.
clear; clc;
sol = ode45(@ode_fun, [0 1], [1; 0; 0; 0; 0; 1]);
function dydt = ode_fun(t, y)
rhodm = 0.8;
rho = 1.0;
G = 0.000000000066743;
H0 = 1; %Model dependent?
Omr = 0.0000463501;
Omm = 0.2514;
Omk = 0;
OmLa = 0.6847;
k=1.0;
theta0 = y(1);
theta1 = y(2);
Phi = y(3);
delta = y(4);
v = y(5);
a = y(6);
dydt = zeros(size(y));
dydt(1) = -dydt(5) - k.*theta1;
dydt(2) = -k./3.*(Phi-theta0);
dydt(3) = -3.*dydt(5) - 1i.*k.*v;
dydt(4) = 1i.*k.*Phi - dydt(6)/a.*v;
dydt(5) = (4.*pi.*G.*a.^2.*(rhodm.*delta + 4.*rho.*theta0) - k.^2.*Phi ).*a/(3.*dydt(6)) - dydt(6)/a.*Phi;
dydt(6) = H0 * a .* sqrt(Omr ./ a.^4 + Omm ./ a.^3 + Omk ./ a.^2 + OmLa);
end

3 Kommentare

James Tursa
James Tursa am 12 Mai 2023
Bearbeitet: James Tursa am 12 Mai 2023
Please post an image/pic of the differential equations you are solving. If k is supposed to be a variable, what are the differential equations governing it? Why isn't it one of your y elements?
bozo
bozo am 12 Mai 2023
@James Tursa I've updated with the differential equations
Torsten
Torsten am 12 Mai 2023
You forgot the 5th equation.

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Torsten
Torsten am 11 Mai 2023

1 Stimme

You use dydt(5) and dydt(6) before they have been assigned their values:
dydt(1) = -dydt(5) - k.*theta1;
dydt(2) = -k./3.*(Phi-theta0);
dydt(3) = -3.*dydt(5) - 1i.*k.*v;
dydt(4) = 1i.*k.*Phi - dydt(6)/a.*v;
dydt(5) = (4.*pi.*G.*a.^2.*(rhodm.*delta + 4.*rho.*theta0) - k.^2.*Phi ).*a/(3.*dydt(6)) - dydt(6)/a.*Phi;
Use instead a modified order in the calculation of the derivatives:
dydt(6) = H0 * a .* sqrt(Omr ./ a.^4 + Omm ./ a.^3 + Omk ./ a.^2 + OmLa);
dydt(5) = (4.*pi.*G.*a.^2.*(rhodm.*delta + 4.*rho.*theta0) - k.^2.*Phi ).*a/(3.*dydt(6)) - dydt(6)/a.*Phi;
dydt(1) = -dydt(5) - k.*theta1;
dydt(2) = -k./3.*(Phi-theta0);
dydt(3) = -3.*dydt(5) - 1i.*k.*v;
dydt(4) = 1i.*k.*Phi - dydt(6)/a.*v;

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R2021b

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am 11 Mai 2023

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am 12 Mai 2023

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