Extract matrices of a particular size

Suppose there a cell containing matrices of different sizes. How can I extract all the (1x16) matrices in the same order which was present in the cell and store them in a different cell?

[LUI PAUL]

try it

result=cat([1],cellData1{:,:}); %Converting celldata to double.

Answer 1

[James Tursa]

C = your cell array
DesiredSize = whatever; % e.g. [1 16]
Z = cellfun(@size,C,'UniformOutput',false); % get matrix sizes
X = cellfun(@isequal,Z,repmat({DesiredSize},size(Z))); % which ones match desired size
D = C(X); % Extract them into another cell array

[Michael Haderlein]

In principle, yes, but it looks to me as if there's are more straight-forward way of getting X:

 C={rand(3) rand(1,16) rand(1,9) rand(1,16)};
 DesiredSize=[1 16];
 X=cellfun(@(c) isequal(size(c),DesiredSize),C);
 D=C(X);

[Hamza Ahmed]

Hello i wanna loop through this

lets just say i have a 1*78 cell array and each cell has matrix of 2 columns but different number of rows my question is that how will I extract all the matrices which have number of rows greter then 2 from that cell array? any help in this regard will be much appreciated Thankyou

Answer 2

[Andrei Bobrov]

[a,b] = cellfun(@size,C);
out = C(ismember([a;b]',[1,16],'rows'));

Answer 3

[ankit]

I tried

   z=cellfun(@(x) length(x),new_cell); %displays the lengths of the matrices of the cell
    pos=find(z==16);

now I can get positions of all the 1x16 matrices

[Andrei Bobrov]

No, e.g.:

>> C = {randi(20,4,4);randi(10,1,16);randi(20,1,16);randi(15,16,3)};
>> ii = cellfun(@length,C)
ii =

             4
            16
            16
            16

>>