How to create a column vector corresponding to number of rows of matrices using for loop?

Hi everyone,

I am trying to analyze data corresponding to animal behavioral trials. I have a bunch of x by 15 matrices (each represents 1 trial's data; x represents video frames and ranges from 1200 to 3000, but always 15 columns).

I am trying to use a for loop to create a column vector for each of the trials that contains the number of rows for that trial's data. Let's call it nframes. So for example if the trial has 1500 frames, the nframes value for that trial would show up as a column vector with 1500 rows numbered 1 through 1500.

Code thus far (removing unnecessary parts):

for i_trial = i_probe_trials' % for all trials of interest

load(video_trial{i_video_trial}(1:end-2)); % load video data

nframes = ???

traj_y = dlcmat(:,(marker_num_plot-1)*3+2); % get trace from trial

end

What is the easiest way to do this? I've tried a number of things and I'm stuck.

Thank you!

Answer 1

[Rik]

You should always load to a variable. Then it is a lot easier to see where your variables come from. For this case I expect you need to use the size function. (I had to guess the variable name and this loop is overwriting the results)

for i_trial = i_probe_trials'   % for all trials of interest 
  S=load(video_trial{i_video_trial}(1:end-2));    % load video data
  dlcmat=S.dlcmat;
  nframes = size(dlcmat,1); 
  traj_y = dlcmat(:,(marker_num_plot-1)*3+2);  % get trace from trial
end

[Elise Mangin]

Hi Rik,

This is helpful!, but it makes nframes read as just a number (1630). I'd like it to read as a column vector (1 column with rows numbering sequentially from 1 to 1630). I was using the length function before, but size function does the same thing in this case.

Thank you for explaining loading to a variable though. Helpful information.

[Rik]

You mean you want nframes = 1:size(dlcmat,1);?

[Elise Mangin]

YES! Thank you. It works now with this code.

I apologize - I am still learning. Thanks so much for the help!