How can i display this user defined matrix made with a loop

I used a loop to create a user defined matrix and i want to display in column form not row form. I can not get the code to fprintf in column form, any help would be greatly appreciated.

n = input('Enter your number of rows: ');
m = input('Enter your number of columns: ');
fprintf('Select a function:\n');
fprintf('1) Add\n');
fprintf('2) Subtract\n');
fprintf('3) Multiply\n');
fprintf('4) Divide\n');
fun_choice = input('Enter your choice (1:4): ');
% Calculation section:
matrix = zeros(n, m);
for k = 1:n
    for h = 1:m
        if fun_choice == 1 
            matrix(k, h) = k + h;
        elseif fun_choice == 2 
            matrix(k, h) = k - h;
        elseif fun_choice == 3 
            matrix(k, h) = k * h;
        elseif fun_choice == 4 
            matrix(k, h) = k / h;
        end
    end
end

[Les Beckham]

What do you mean by "column form"?

[Dyuman Joshi]

Say n=4, m=5 and fun_choice is 1. What is the output you want?

n=4;m=5;
matrix = zeros(n, m);
fun_choice = 1;
for k = 1:n
    for h = 1:m
        if fun_choice == 1 
            matrix(k, h) = k + h;
        elseif fun_choice == 2 
            matrix(k, h) = k - h;
        elseif fun_choice == 3 
            matrix(k, h) = k * h;
        elseif fun_choice == 4 
            matrix(k, h) = k / h;
        end
    end
end
matrix

matrix = 4×5

2 3 4 5 6 3 4 5 6 7 4 5 6 7 8 5 6 7 8 9

Answer 1

[KSSV]

n=4;m=5;
matrix = zeros(n, m);
fun_choice = 1;
for k = 1:n
    for h = 1:m
        if fun_choice == 1 
            matrix(k, h) = k + h;
        elseif fun_choice == 2 
            matrix(k, h) = k - h;
        elseif fun_choice == 3 
            matrix(k, h) = k * h;
        elseif fun_choice == 4 
            matrix(k, h) = k / h;
        end
    end
end
fprintf('%f\n',matrix(:))  % print as column using fprintf 
matrix(:)   
fprintf('%f %f %f %f\n',matrix)   % print like matrix using fprintf 
matrix 

Answer 2

[Walter Roberson]

My suspicion is that you have a situation something like

M = magic(4)

M = 4×4

16 2 3 13 5 11 10 8 9 7 6 12 4 14 15 1

fprintf('%d %d %d %d\n', M)

16 5 9 4
2 11 7 14
3 10 6 15
13 8 12 1

and you are noticing that the output rows such as 16 5 9 4 do not correspond to the rows of the data, like 16 2 3 13

If so, there are two ways to proceed:

First you can do

fprintf('%d %d %d %d\n', M.')

16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1

The number of %d should be the same as the number of columns of data.

Or, you can use

compose("%d %d %d %d", M)

ans = 4×1 string array
    "16 2 3 13"
    "5 11 10 8"
    "9 7 6 12"
    "4 14 15 1"

Or you can combine

fprintf('%s\n', compose("%d %d %d %d", M))  %format is used once per entry in the string array

16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1

or

fprintf('%s\n', join(compose("%d %d %d %d", M),newline))  %format is used once

16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1