How to round numbers using the decimals as a probability?

Hi, I am trying to create code where the decimals are used as probability of how the value is rounded. For example, I have array of the following values: [ 1.04 ; 0.96 ; 0.22 ; 1.56 ] and for the first element there is a 4% chance the value gets rounded up to 2 and a 96% chance it gets rounded to 1. For the second element there is a 96% probability that it gets rounded up to 1 and a 4% it gets rounded to 0.

[Walter Roberson]

What is the rule? Round down 96% of the time for values with even row numbers, and round down 96% of the time for values with odd row numbers? If so then should that be modified if there are multiple columns ?

Answer 1

[David Hill]

A=10*rand(1,10)

A = 1×10

3.8438 8.9825 9.7798 3.3108 6.2760 5.4551 4.8986 1.2530 4.2234 9.1930

B=floor(A)+((A-floor(A))>rand(1,10))

B = 1×10

3 9 9 3 7 6 5 1 5 9

[Walter Roberson]

Ah, I didn't think of that possibility !

[Aron]

Thanks, I changed it to

A=10*rand(1,10)

B=floor(A)+((A-floor(A))>rand(1,1))

Because otherwise B is the of the size 3x10.

[Walter Roberson]

No, each entry in A should be rounded individually.

B=floor(A)+((A-floor(A))>rand(size(A)))