Hi all,
I already have a step up. i wish i had one down. how do i change my code?
aux1=70*1200;
aux2=70.2*1200;
for k=1:aux1
v_aux(k)=0.1;
end
for k=aux1:aux2
v_aux(k)=v_aux(k-1)+(0.3-0.2)/(360);
end
for k=aux2:240000
v_aux(k)=0.31;
end
for k=1:240000
v_aux(k)=v_aux(k)+(rand-0.5)*0.01;
end;
X2=v_aux';
Thanks in advance

 Akzeptierte Antwort

Sulaymon Eshkabilov
Sulaymon Eshkabilov am 1 Apr. 2023

0 Stimmen

In this exercise, no need to use a loop to obtain a step fcn. Way1 is using simple matrix operation:
aux1=70*1200;
aux2=70.2*1200;
X=0.1*ones(1,aux1);
X(70*1200:70.2*1200) =0.1;
X(70*1200:70.2*1200) = X((70*1200)-1:(70.2*1200)-1)+(0.3-0.2)/(360);
X(aux2:240000) = 0.31;
X(1:240000)=X(1:240000)+(rand(1,240000)-0.5)*0.01;
figure
plot(X)
%%
Way 2 is using heaviside() fcn:
syms x
figure
fplot(0.31*heaviside(x - .31), [0, 2]), shg

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