Hi All,
I need mutiple values for x for a range of t, it is only keeping the last variable, What do I do?
Here is my code
for t = 0:1:100
x = (0.5exp(2*sin(t)))/(10.5*exp(2*sin(t)));
end
Thank you

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Torsten
Torsten am 11 Mär. 2023

0 Stimmen

You mean
t = 0:1:100;
x = 0.5*exp(2*sin(t))./(10.5*exp(2*sin(t)));
plot(t,x)
(which is equal to 0.5/10.5=0.04761... because exp(2*sin(t)) cancels out) ?

3 Kommentare

Alice K
Alice K am 11 Mär. 2023
Bearbeitet: Walter Roberson am 11 Mär. 2023
Sorry there was a typo, this is my full code
I need to plot x againts M
t = 0:1:100;
u = 1;
v = 1;
A = 0.1
for t = 0:1:100
x = (A.*exp(u.*sin(t)))/(1+A.*exp(u.*sin(t)))
end
M = (1+v.*cos(t).*A.*exp(u.*sin(t))+v.*cos(t)-1)/(1+A.*exp(u.*sin(t)));
figure
plot(M,x)
I am getting nothing on the graph.
You should avoid using the / operator, except possibly for the case of dividing by a literal constant. The / operator is not the division operator: it is the matrix division operator, with A/B being similar to A*pinv(B) or similar to least-squares regression. Use ./ for the division operator
I would suggest to you that in the cases where you really do want to use matrix division or matrix least-squares that instead of A/B that you use (B'\A')' instead -- the use of \ emphasizes the matrix operation.
t = 0:1:100;
u = 1;
v = 1;
A = 0.1
A = 0.1000
x = (A.*exp(u.*sin(t))) ./ (1+A.*exp(u.*sin(t)))
x = 1×101
0.0909 0.1883 0.1989 0.1033 0.0448 0.0369 0.0703 0.1617 0.2119 0.1312 0.0549 0.0355 0.0552 0.1321 0.2122 0.1608 0.0698 0.0368 0.0451 0.1041 0.1995 0.1876 0.0902 0.0411 0.0389 0.0805 0.1765 0.2065 0.1159 0.0490
M = (1+v.*cos(t).*A.*exp(u.*sin(t))+v.*cos(t)-1) ./ (1+A.*exp(u.*sin(t)));
figure
plot(M,x)
Alice K
Alice K am 11 Mär. 2023
It Works,
Amazing, Thank you

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