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New Workplace variable from Table

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Nathan Kelly
Nathan Kelly am 9 Mär. 2023
Beantwortet: Steven Lord am 9 Mär. 2023
Say I have a Table with Variable headers for each column such as below.
Tp = table(categorical({'M';'M';'F';'F';'F'}),[38;43;38;40;49],...
[71;69;64;67;64],[176;163;131;133;119],...
'VariableNames',{'Gender' 'Age' 'Height' 'Weight'})
If I look at the table in the variable window I can select the column by hand and create a new workplace variable/array from the data , named after the headers (VariableNames',{'Gender' 'Age' 'Height' 'Weight'})) with the data of that variable.
Is there a way to code a script to do this without manually picking the columns? Or a way to create new workplace variables from list?

Akzeptierte Antwort

Steven Lord
Steven Lord am 9 Mär. 2023
Is there a way to code a script to do this without manually picking the columns? Or a way to create new workplace variables from list?
Can you dynamically create variables with names automatically generated from table variable names? Yes.
Should you do this? The general consensus is no. That Answers post explains why this is generally discouraged and offers several alternative approaches.
Depending on what you want to do with those variables the varfun function may be of interest to you.

Weitere Antworten (1)

Cameron
Cameron am 9 Mär. 2023
Tp = table(categorical({'M';'M';'F';'F';'F'}),[38;43;38;40;49],...
[71;69;64;67;64],[176;163;131;133;119],...
'VariableNames',{'Gender' 'Age' 'Height' 'Weight'});
Age = Tp.Age;
Gender = Tp.Gender;
disp(Age)
38 43 38 40 49

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R2020b

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