Filter löschen
Filter löschen

t test ( not sure if my implementation is correct)

2 Ansichten (letzte 30 Tage)
Alexander Guillen
Alexander Guillen am 28 Feb. 2023
Suppose that I have two groups, N and R. Each group contains four columns which represent different subjects. For example (hypothetically):
N1 = [1:5]' .... N4 = [1:5]' so that N = { N1,N2,N3,N4}
R1 = [1:5]'.... R4 = [1:5]' so that R = {R1...R4}
Is it possible to enable a loop which which can perform the t-test so that I can avoid this manually:
h = ttest(N1,R1);
.
.
.
h = ttest(N1,R4);
---
h = ttest(N2,R1);
.
.
.
h = ttest(N2,R4); and so on
I understand it may be wrong my implementation of the t-test. But I would like to put into a loop what I just described. Any guidance and help will be appreciated.

Akzeptierte Antwort

David Hill
David Hill am 28 Feb. 2023
N=randi(100,5,4);%your matrix;
R=randi(100,5,4);%your matrix
h=1;
for n=1:4
for r=1:4
H(h)=ttest(N(:,n),R(:,r));
h=h+1;
end
end
H
H = 1×16
0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0
  2 Kommentare
Alexander Guillen
Alexander Guillen am 28 Feb. 2023
wow thank you
Alexander Guillen
Alexander Guillen am 28 Feb. 2023
By any chance, do you know how I can display the columns from N and R which h = 1?

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu MATLAB finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by