Convert datetime to numeric - preserve date format

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Elin Jacobs
Elin Jacobs am 27 Feb. 2023
Kommentiert: Campion Loong am 29 Mär. 2023
I have a timetable with dates (datetime data type) in the format 'yyyy-MM-dd HH:mm'. I want to convert these to a numeric data type (double) but keeping the exact numbers of each date such that the datetime '2023-02-27 14:00' is converted to the double '202302271400'. The function yyyymmdd() allows me to do this for the date, but not the hour and minute, and none of the other built in functions to convert to datenumber seem to have this option. Thanks for any insights to this problem.

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Les Beckham
Les Beckham am 27 Feb. 2023
Bearbeitet: Les Beckham am 28 Feb. 2023
Edited to work with datetime array vs a single datetime.
d = datetime(['2023-02-27 14:00'; '2023-02-27 15:00']) % test data - replace with your timetable
d = 2×1 datetime array
27-Feb-2023 14:00:00 27-Feb-2023 15:00:00
s = string(d, 'yyyyMMddHHmm')
s = 2×1 string array
"202302271400" "202302271500"
format long
% f = cellfun(@(s)sscanf(s, '%f'), s) % original method of converting to double
f = double(s) % An easier/cleaner method. Thanks to Walter for reminding me about this.
f = 2×1
1.0e+11 * 2.023022714000000 2.023022715000000
compose('%.0f', f)
ans = 2×1 cell array
{'202302271400'} {'202302271500'}
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Campion Loong
Campion Loong am 29 Mär. 2023
@Elin Jacobs Thanks for confirming. That (unfortunately) makes sense.

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