Why is my function not working?

I am very new to MATLAB, as in, started two days ago because I'm trying to translate some code from mathematica.

For context x0 = 1 and x,x2 are undefined in this function

function [f355] = f355(x,x0,x2)
%UNTITLED4 Summary of this function goes here
%   Detailed explanation goes here
if x >= 0
    f355 = (Omega00)*sqrt((1)+((Lambda355*x)/(pi*(Omega00))^2));
elseif (x<=(x2+x1+x0))&&(x>=x0)
    f355 = NewBWaist(Omega00,x0,f,Lambda355)*sqrt((1)+(Lambda355*(x-x0-x1)/(pi(Omega01)^2))); 
else x >= (x0+x1+x2)
    f355 = NewBWaist(NewBWaist(Omega00,x0,f1U,Lambda355),x2,f2U,Lambda355)*sqrt((Lambda355(x-sumxU))/(pi*(Omega02)^2));
end

When I run "f355(10,1,20)" I get an error

"Index in position 1 exceeds array bounds. Index must not exceed 1.

Error in m118codeInprogress (line 111)

f355(10,1,20)"

Any advice would be most welcome. Thanks.

[Dyuman Joshi]

There are un-defined variables in your code - Omega00, Lambda355, etc. Please specify their values.

Also, do not use the same name for function and a variable, as it overwrites the assignment.

[Theobold]

Apologies,

Omega00= 3.5

Lambda355= 0.000355

The rest of the variables are themselves defined by other functions with yet more variables. The other functions are all working though.

[Dyuman Joshi]

Rename your output variable name and run your code. As other functions are working properly, your code should work after the correction as well.

Answer 1

[Jan]

Avoid using the name of the function as name of the output. This is confusing only.

Which is the failing line? In this line f355 is used as a variable, not as a function.

See this example:

sin(0.1)   % Fine
sin = 15;  % Now sin is a variable
sin(0.1)   % Error: 0.1 is no valid index

[Theobold]

Right I see, I ran a calculation earlier (since deleted) with f355= so I guess it's now assigned as a variable?

Thanks for the advice.