Hello everyone,
i am trying to use imread to read multiple images in a for loop.
path='Z:\collect_data';
for t=1:length(nan_rows)
image_test=imread([path,'nan_rows' (t)]);
%further coding
end
the 'nan_rows' here is a string array.
I want to read the images which the file names are stored in the array.
Does anyone know how to do it?
Thanks a lot in advance!

 Akzeptierte Antwort

VBBV
VBBV am 23 Feb. 2023
Bearbeitet: VBBV am 23 Feb. 2023

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image_test{t}=imread([path,'nan_rows' num2str(t)])

7 Kommentare

VBBV
VBBV am 23 Feb. 2023
Bearbeitet: VBBV am 23 Feb. 2023
Use a cell array to store images. While concatenation of path with filenames, you need to use num2str
Yunwei
Yunwei am 23 Feb. 2023
Hi,
sorry to say it but the script you posted is not really working,
It causes a error massage saying "File "Z:\collect_data\nan_rows1" does not exist."
I need to get the data array of "nan_rows".
VBBV
VBBV am 23 Feb. 2023
Bearbeitet: VBBV am 23 Feb. 2023
Is nan_rows a file or folder ? If it's file then it needs additional string called file extension. E.g
image_test{t}=imread([path,'nan_rows', num2str(t),'.jpg'])
Also, check whether the file exists in the folder collect_data
VBBV
VBBV am 23 Feb. 2023
Bearbeitet: VBBV am 23 Feb. 2023
If nan_rows is folder, then you need to concatenate filename also to the path. Can you share the path and/or files ?
Yunwei
Yunwei am 23 Feb. 2023
nan_row is an array.
I have attached it here.
According to the question, the filenames are in a string array, so I don't know why we're generating number suffixes at all. If we are to generate number suffixes, then we'd actually need to know how they're formatted.
% you have your base path
fprefix = fullfile(matlabroot,'toolbox','images','imdata');
% and you say you have a string array of filenames
fnames = ["cameraman.tif" "tire.tif" "coins.png" "strawberries.jpg"];
nfiles = numel(fnames);
image_test = cell(nfiles,1); % preallocate
for k = 1:nfiles
image_test{k} = imread(fullfile(fprefix,fnames(k)));
end
montage(image_test)
Build the path with fullfile(). If you have to programmatically construct the filename, using sprintf() is simpler and more readable imo.
Yunwei
Yunwei am 23 Feb. 2023
That's exactly what l need.
Thank you so much for your help!

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