Array indices must be positive integers or logical values.

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Angelina
Angelina am 21 Feb. 2023
Bearbeitet: Askic V am 21 Feb. 2023
I have a function that keeps giving me this error in line 2. I am trying to plot a third order differential equation. I was previously experiencing a different error, but now I have this. I am creating a function and then calling it when I use ode45. Thank you in advance!
function dYdt = problem03ODEFunction(t,y)
x1 = y(t);
X2 = dx1/dt == dy/dt;
X3 = dx2/dt == d2y/dt2;
f(t) = heaviside(t-1) - heaviside(t-10);
dx3dt = d3y/dt3 == f(t) - (19/12)*d2y/dt2 - (19/24)*dydt - (1/8)*y(t);
end
  3 Kommentare
Angelina
Angelina am 21 Feb. 2023
The purpose of the second line is to define x1. x1 is used in the following line. Basically the idea is to change the equation from a third order to a second order.
Dyuman Joshi
Dyuman Joshi am 21 Feb. 2023
Okay, but what about y and t? What are they supposed to be? y as a function of t? or otherwise? Please specify.

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Antworten (1)

Askic V
Askic V am 21 Feb. 2023
Bearbeitet: Askic V am 21 Feb. 2023
It seems to me that you actually want this:
[t,y]=ode45(@problem03ODEFunction,[0 20],[2 0 0]);
plot(t,y(:,1))
hold on; grid on;
plot(t,y(:,2))
leg = legend('y(t)', '$\frac{dy}{dt}$','interpreter','latex');
leg.FontSize = 12;
function dy = problem03ODEFunction(t,y)
dy = zeros(3,1);
dy(1) = y(2);
dy(2) = y(3);
f = heaviside(t-1) - heaviside(t-10);
dy(3) = f - (19/12)*dy(2) - (19/24)*dy(1) - (1/8)*y(1);
end

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