Create a random Matrix
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I have a 8 column vector n*1. Can I create a Random matrix of n*8?
The function must take one value from each vector and create a matrix with 8 columns and n rows.
Please help me :-)
2 Kommentare
Jan
am 24 Okt. 2011
"I have a 8 column vector" sounds like a single vector. But "from each vector" might mean n vectors. Confusing.
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Andrei Bobrov
am 24 Okt. 2011
A1,A2,..,A8 - your vectors (nx1), let n = 5;
for j1 = 1:8, eval([sprintf('A%d',j1),'=randi(20,5,1)']); end
A = eval(['[',sprintf('A%d,',1:8),']'])
out=A(bsxfun(@plus,cell2mat(arrayfun(@(x)randperm(n)',(1:8),'un',0)),(0:7)*n))
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Walter Roberson
am 24 Okt. 2011
rv(:,1) = randomvector1;
rv(:,2) = randomvector2;
rv(:,3) = randomvector3;
....
rv(:,4) = randomvector4;
rants = zeros(8, n);
for K = 1:n
rants(:,K) = A Random Selection of One Entry Per Column from rv
end
How to do "A Random Selection of One Entry Per Column from rv" is left to you to work on in more detail. I will hint that it involves using rand().
3 Kommentare
Walter Roberson
am 30 Okt. 2011
floor(1 + n * rand())
will give you a random row number.
If I say much more than I will be completing your assignment for you.
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