Im trying to get a step response for a transfer function but having trouble implementing it in matlab.
H(s)=K/(t*s+1)
Code:
sym k
sym t
sys = tf(k,[t 1])
step(sys)

 Akzeptierte Antwort

Star Strider
Star Strider am 11 Feb. 2023
Bearbeitet: Star Strider am 11 Feb. 2023

1 Stimme

The Control System Toolbox functions require numerical values.
It is possible to create an anonymous function with your code, and you can then use numerical values for ‘k’ and ‘t’ with it —
sys = @(k,t) tf(k,[t 1]);
k = 0.5;
t = 2;
figure
step(sys(k,t))
grid
The Symbolic Math Toolbox can be used to derive transfer functions. The sym2poly and double functions are helpful in that situation.
EDIT — Corrected typographical error.
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2 Kommentare

Zain Ali
Zain Ali am 11 Feb. 2023
Thank you!
Star Strider
Star Strider am 11 Feb. 2023
As always, my pleasure!

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Weitere Antworten (1)

Walter Roberson
Walter Roberson am 11 Feb. 2023

1 Stimme

tf() is part of the Control System Toolbox, which is not designed at all to be able to use symbolic expressions.
The Control System Toolbox has no capacity to draw a family of plots -- the plots for all of the different shapes that can be generated by using different K and t values. K might be negative. K might be 0. t might be negative. K or t might be complex.
You can work symbolically, such as
syms k t s
sys = k/(t*s + 1)
sys = 
isys = ilaplace(sys, s)
isys = 
but the symbolic toolbox has no way to draw families of plots either.

3 Kommentare

Paul
Paul am 11 Feb. 2023
The Control System Toolbox has some capacity to draw a family plots where the user defines a parametric model and the values to use in the parametric model. For example, see this doc page.
Mixing t and s in an expression for a Laplace transform as in this Question is asking for nothing but trouble.
Walter Roberson
Walter Roberson am 11 Feb. 2023
The Control System Toolbox has very limited capacity to work with systems with parameters in them. There is some capacity; see https://www.mathworks.com/matlabcentral/answers/305339-how-to-create-a-transfer-function-with-gain-k#answer_236890 . In each case, at any time the parameter is considered to have a specific value; the facilities that exist are there to make it easier to change the value of the parameter, potentially using automatic tuning.
Zain Ali
Zain Ali am 11 Feb. 2023
Thank You!

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