how to rotate image using function notation

8 Ansichten (letzte 30 Tage)
mark palmer
mark palmer am 7 Feb. 2023
Kommentiert: Chris am 7 Feb. 2023
How do I write Matlab code using functions to make a rotation on an image? THis is all I've got so far, and I'm probably way off...
I = 'cameraman.jpg';
fa = 45;
f1 = @(xy) xy(:,1) .* cosd(fa) + xy(:,2) .* sind(fa);
f2 = @(xy) -xy(:,1) .* sind(fa) + xy(:,2) .* cosd(fa);
ifcn1 = @(xy) f1(xy);
tform1 = geometricTransform2d(ifcn1);
Rin = imref2d(size(I),[-1 1],[-1 1]);
Rout = imref2d(size(I),[-1 1],[-1 1]);
rho1a = imwarp(I,Rin,tform1,'OutputView',Rout,FillValues=0);

Akzeptierte Antwort

Chris
Chris am 7 Feb. 2023
If you're using imwarp, you might as well use imrotate, no? You'd be using the function imrotate() to rotate an image, if that's really your goal.
fa = 45;
I = imread('cameraman.tif');
imrot = imrotate(I,fa);
imshow(imrot)
If you want an anonymous function, like you're using...
rotateImage = @(im, ang) imrotate(im, ang);
imrot = rotateImage(I, fa);
imshow(imrot)
You could also make a standalone function, in a file of the same name or at the bottom of a script, that accepts inputs and outputs the rotated image, and does whatever else you want with the input.
imrot = rotImFun(I, fa);
imshow(imrot);
function out = rotImFun(im, ang)
out = imrotate(im, ang);
end
  3 Kommentare
mark palmer
mark palmer am 7 Feb. 2023
Bearbeitet: mark palmer am 7 Feb. 2023
IS there an alternate way to do this with trig functions within an anonymous function? I know it isn't the easiest way, I'm just trying to learn.
Chris
Chris am 7 Feb. 2023
I'm unaware of a method that doesn't require a complex series of operations, which a single anonymous function isn't really suited for. That doesn't mean it doesn't exist--it just means I don't have an answer.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Images finden Sie in Help Center und File Exchange

Produkte


Version

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by