How to locate X value for a given Y value
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David Harra
am 1 Feb. 2023
Beantwortet: Star Strider
am 2 Feb. 2023
I have Data which is Time along the x-axis and amplitude along the y -axis.
I want to know the exact time at a given value of amplitude. Its probably just one line of code but I can't seem to figure it out.
Any help would be appreciated.
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Star Strider
am 2 Feb. 2023
In the absence of the data, getting an independent variable valuex ‘x’ from an dependent variable value ‘y’ is relatively straightforward.
Try soemthing like this —
x = linspace(0, 20, 201);
y = besselj(0, x);
yval = linspace(-0.2, 0.2, 6);
for k1 = 1:numel(yval)
zxi = find(diff(sign(y-yval(k1))));
for k2 = 1:numel(zxi)
idxrng = max(1,zxi(k2)-1) : min(numel(x), zxi(k2)+1);
xv(k1,k2) = interp1(y(idxrng), x(idxrng), yval(k1));
end
end
for k1 = 1:size(xv,1)
xv(k1,xv(k1,:)==0) = NaN;
end
figure
plot(x, y)
hold on
for k1 = 1:size(xv,1)
plot(xv(k1,:), ones(size(xv(k1,:)))*yval(k1), 's')
end
yline(yval, ':')
hold off
grid
xlabel('X')
ylabel('Y')
.
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the cyclist
am 1 Feb. 2023
Bearbeitet: the cyclist
am 1 Feb. 2023
It would be helpful if you uploaded the data. You can use the paper clip icon in the INSERT section of the toolbar.
It seems like you need either
% The exact value appears in the amplitude vector, and want to find what Time it occurs
Time(amplitude == value) % be careful here if you are comparing floating point values
or
% The exact value does not appear in the amplitude vector, so you want the
% first Time where you surpass that value
Time(find(amplitude>value,1)) % this assume the values of amplitude and time are sorted appropriately
You might also want to interpolate between times, but be more exact. Then you'll need the interp1 function.
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