Convert uint8 vector to float

114 Ansichten (letzte 30 Tage)
hohohihi
hohohihi am 30 Jan. 2023
Kommentiert: Star Strider am 7 Mär. 2023
Hi All,
i have a .mf4-measurement data in uint8:
1×20 uint8 row vector
132 132 132 132 132 132 133 133 133 133 134 138 170 214 222 226 224 216 215 215
is there a way to convert it to these physical values (float)?
0.01 0.01 0.01 0.01 0.01 0.01 0.02 0.02 0.02 0.02 0.03 0.07 0.39 0.83 0.91 0.95 0.93 0.85 0.84 0.84
Thank u and kind regards,
  2 Kommentare
Les Beckham
Les Beckham am 30 Jan. 2023
Normally this would be as simple as converting the input data to double and multiplying by a scale factor. Your example values, however don't have a simple linear relationship between the input data and the example output data (see below).
Can you clarify how your example "physical values" were generated?
in = uint8([132 132 132 132 132 132 133 133 133 133 134 138 170 214 222 226 224 216 215 215])
in = 1×20
132 132 132 132 132 132 133 133 133 133 134 138 170 214 222 226 224 216 215 215
out = [0.01 0.01 0.01 0.01 0.01 0.01 0.02 0.02 0.02 0.02 0.03 0.07 0.39 0.83 0.91 0.95 0.93 0.85 0.84 0.84]
out = 1×20
0.0100 0.0100 0.0100 0.0100 0.0100 0.0100 0.0200 0.0200 0.0200 0.0200 0.0300 0.0700 0.3900 0.8300 0.9100 0.9500 0.9300 0.8500 0.8400 0.8400
SF = out./double(in)
SF = 1×20
0.0001 0.0001 0.0001 0.0001 0.0001 0.0001 0.0002 0.0002 0.0002 0.0002 0.0002 0.0005 0.0023 0.0039 0.0041 0.0042 0.0042 0.0039 0.0039 0.0039
plot(SF)
grid on
hohohihi
hohohihi am 30 Jan. 2023
Bearbeitet: hohohihi am 30 Jan. 2023
HI Les,
thank u for ur answer.
Thats my problem, i've tried many conversion, also with im2double, but unfortunately it did not work.
I use ETAS-MDA Tool to analyze my .mf4-measurement, on that tool i do have 3 options to view my data:
  • Physical Value
  • HEX
  • and Decimal (RAW)
When i set the dataview to physical value, i got that values (0.01 0.01 0.01 0.01 ...).
When i set the datareview to decimal (RAW), i got the uint8 values (132 132 132 132...)
it happened too, when i imported my mf4-measurement to MATLAB by mdf-reader, thats why i'm trying to find a way to get the physical values by converting..
Kind regards,

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Star Strider
Star Strider am 30 Jan. 2023
Since you apparently know the mapping, one option is to simply calculate a linear regression (assuming that a linear relation exists) —
u = uint8([132 132 132 132 132 132 133 133 133 133 134 138 170 214 222 226 224 216 215 215]);
v = [0.01 0.01 0.01 0.01 0.01 0.01 0.02 0.02 0.02 0.02 0.03 0.07 0.39 0.83 0.91 0.95 0.93 0.85 0.84 0.84];
B = [132 1; 226 1] \ [0.01; 0.95] % Linear Regression
B = 2×1
0.0100 -1.3100
f = [double(u(:)) ones(size(u(:)))] * B;
figure
plot(double(u), v, '.', 'DisplayName','Data')
hold on
plot(double(u), f, '-', 'DisplayName','Linear Regression')
hold off
grid
xlabel('u')
ylabel('f')
legend('Location','N')
It would likely help to know what the data represent and what the actual conversion is. This approach is a guess that may not work on data other than those in the range of the ‘u’ vector.
.
  2 Kommentare
hohohihi
hohohihi am 7 Mär. 2023
Very good idea, I'll check few of measurement data to confirm the linear relation.
Thank you Star!! :-)
Star Strider
Star Strider am 7 Mär. 2023
As always, my pleasure!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by