Simulink "MATLAB Function" block and extremum value
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Hello. I am trying to use single input and single output Simulink matlab code function block: MATLAB function. I use the input value "u" to calculate the output value "y", which should be the maximum value of the function "factor (v, u)". The function "factor" depends on the Simulink block input "u" as well as the value which is needed to be found as output ("y" or "result" or "fcn(u)").
How could I find the maximum extremum value for the function factor(v,u) and which value for parameter "v" is needed to have the maximum value for factor (v, u) function? The result or output of the Simulink function block is the parameter value "v" which gives the maximum value for factor (v,u). How could I do it in correct way?
function y = fcn(u)
%function factor(v,u)
factor(v,u)=(18/(1/(u+0.01*v)-0.05/(v^3+1))-0.4*v-1)...
*exp(-2/(1/(u+0.01*v)-0.05/(v^4+1)))+0.8*u-6;
%end
fcn(u)=v=????....
result=fcn(v,u);
y = result;
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Antworten (1)
Sulaymon Eshkabilov
am 29 Jan. 2023
Note that there are a couple of important points here. (1) v input argument values have to be given/known to perform the calculations of your stated formulation. (2) therefore, there must be two input arguments to MATLAB fcn block. Considerign these two points ehre is the completed code of fcn:
function y = fcn(u, v)
H=(18/(1/(u+0.01*v)-0.05/(v^3+1))-0.4*v-1)...
*exp(-2/(1/(u+0.01*v)-0.05/(v^4+1)))+0.8*u-6;
[~, IDX] = max(H);
y = v(IDX);
One simple simulink model (Sim_Demo.slx) is attached to this post with this code.
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Sulaymon Eshkabilov
am 29 Jan. 2023
Check your problem statement carefully and then v can be defined. As of now, your problem is not explicitly defined for v. Your probelm description states some v variable which is not clear.
Or you are trying to solve/compute the formulation of H(u, v) for different values of v or what?
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