I have the function Z = (1.5-X+X.*Y).^2 +(2.25-X+X.*(Y.^2)).^2+(2.625-X+X.*(Y).^3).^2.
How can I calculate Z(0,0) in my code?

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Matt J
Matt J am 27 Jan. 2023

1 Stimme

Z = @(X,Y) (1.5-X+X.*Y).^2 +(2.25-X+X.*(Y.^2)).^2+(2.625-X+X.*(Y).^3).^2;
Z(0,0)
ans = 14.2031

2 Kommentare

Annelotte
Annelotte am 27 Jan. 2023
This seems to work, but now I get an error on my surf function. Error shows this:
Error using surf (line 71)
Z must be a matrix, not a scalar or vector.
Error in GradientDescentTestFunction (line 27)
surf(X,Y,Z,'EdgeColor','none','LineStyle','none','FaceLighting','phong');
Matt J
Matt J am 27 Jan. 2023
Bearbeitet: Matt J am 27 Jan. 2023
Z is now a function.
surf(X,Y,Z(X,Y),'EdgeColor','none','LineStyle','none','FaceLighting','phong');

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Gefragt:

am 27 Jan. 2023

Bearbeitet:

am 27 Jan. 2023

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