# Legend with certain number of rows and columns

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dj1du am 25 Jan. 2023
Kommentiert: Davide Masiello am 25 Jan. 2023
Hello everyone,
I would like to plot 6 curves in a diagram and the legend should have the first 4 curves in the first column and the last two curves in the second column. How can I arrange this? Thank you very much for your help!
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Askic V am 25 Jan. 2023

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### Akzeptierte Antwort

Davide Masiello am 25 Jan. 2023
Bearbeitet: Davide Masiello am 25 Jan. 2023
Use legendflex from file exchange.
x = linspace(0,1,1000);
n = (1:6)';
y = x.^n;
p = plot(x,y);
title('y = x^n')
legendflex(p,{'n=1','n=2','n=3','n=4','n=5','n=6'},...
'ncol',2,'nrow',4,'anchor',[1 1],'buffer',[10 -10],'box','off')
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dj1du am 25 Jan. 2023
Thank you very much, that looks very good! But I created the six curves by different plot commands, i.e. according to your naming I would introduce variables p1,p2,p3,p4,p5,p6 for each plot. What would be the correct syntax in this case when calling legendflex?
Davide Masiello am 25 Jan. 2023
I guess this could be considered cheating, but it does work
x = linspace(0,1,1000);
n = (1:6)';
y = x.^n;
p1 = plot(x,y(1,:)); hold on
p2 = plot(x,y(2,:));
p3 = plot(x,y(3,:));
p4 = plot(x,y(4,:));
p5 = plot(x,y(5,:));
p6 = plot(x,y(6,:));
title('y=x^n')
legendflex(p1,{'n=1'},'anchor',[1 1],'buffer',[10 -10],'box','off')
legendflex(p2,{'n=2'},'anchor',[1 1],'buffer',[10 -25],'box','off')
legendflex(p3,{'n=3'},'anchor',[1 1],'buffer',[10 -40],'box','off')
legendflex(p4,{'n=4'},'anchor',[1 1],'buffer',[10 -55],'box','off')
legendflex(p5,{'n=5'},'anchor',[1 1],'buffer',[80 -10],'box','off')
legendflex(p6,{'n=6'},'anchor',[1 1],'buffer',[80 -25],'box','off')

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