defining a fitting type
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Wout Laeremans
am 12 Jan. 2023
Bearbeitet: Torsten
am 16 Jan. 2023
I have written a funcion called Even_fit.m and there are 5 coefficients that need to be found from the fit (a,b,c,d,f) and there is one variable N that I want to load from the workspace, which is already fixed before fitting. My question is how I can load this variable in the fit, since when I do:
ft_even = fittype("Even_fit(x,a,b,c,d,f,N)");
It will also take N as a fitting coefficient, which I do not want.
Thank you!
0 Kommentare
Akzeptierte Antwort
Torsten
am 12 Jan. 2023
Bearbeitet: Torsten
am 12 Jan. 2023
My guess is
fitType = @(x,a,b,c,d,f)Even_fit(x,a,b,c,d,f,N);
fit(x,y,fitType)
2 Kommentare
Torsten
am 16 Jan. 2023
Bearbeitet: Torsten
am 16 Jan. 2023
Put the vector of the independent variable to the end of the input list for your function "EvenFit":
x = linspace(0,1,10).';
y = 3*x.^2 + 0.1*rand(10,1);
n = 12;
fitType = @(a,b,c,x)Even_fit(x,a,b,c,n);
sol = fit(x,y,fitType)
plot(sol,x,y)
function yfit = Even_fit(x,a,b,c,n)
yfit = a*x.^2+b*x+c;
end
Weitere Antworten (1)
Steven Lord
am 12 Jan. 2023
See the "Create Custom Nonlinear Models and Specify Problem Parameters and Independent Variables" and "Use Anonymous Functions to Work with Problem Parameters and Workspace Variables" examples on the fittype documentation page.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Linear and Nonlinear Regression finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!