Plotting amplitude spectrum of a signal

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Artyom
Artyom am 8 Jan. 2023
Kommentiert: Star Strider am 8 Jan. 2023
i got this sygnal
tmax=0.5;
t=0:0.001:tmax;
fs=1000;
tsamp=0:1/fs:tmax;
f1 = 18;
f2 = 321.37;
y = sin(2*pi*f1*tsamp) + sin(2*pi*f2*tsamp);
figure();
plot(t, y);
grid on;
how do I plot it's amplitude spectrum?

Akzeptierte Antwort

Star Strider
Star Strider am 8 Jan. 2023
Try something like this —
tmax=0.5;
t=0:0.001:tmax;
fs=1000;
tsamp=0:1/fs:tmax;
f1 = 18;
f2 = 321.37;
y = sin(2*pi*f1*tsamp) + sin(2*pi*f2*tsamp);
figure();
plot(t, y);
grid on;
L = numel(t);
Fn = fs/2;
NFFT = 2^nextpow2(L);
FTy = fft(y,NFFT)/L;
Fv = linspace(0, 1, NFFT/2+1)*Fn;
Iv = 1:numel(Fv);
figure
plot(Fv, abs(FTy(Iv))*2)
grid on
xlabel('Frequency')
ylabel('Magnitude')
FTyw = fft(y(:).*hann(L),NFFT)/L;
figure
plot(Fv, abs(FTy(Iv))*2)
grid on
xlabel('Frequency')
ylabel('Magnitude')
title('Windowed')
.
  4 Kommentare
Artyom
Artyom am 8 Jan. 2023
it gives me an error in
FTyw = fft(y(:).*hann(L),NFFT)/L;
says "Undefined function 'hann' for input arguments of type 'double'."
could "hann" be replaced somehow?
Star Strider
Star Strider am 8 Jan. 2023
The hann function is part of the Signal Processing Toolbox. Just delete that part of my code, and note that it will still be here if you need it for future reference. (My intent was to demonstrate doing a power-of-2 fft and using a window function.)

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Sulaymon Eshkabilov
Sulaymon Eshkabilov am 8 Jan. 2023
Bearbeitet: Sulaymon Eshkabilov am 8 Jan. 2023
tmax=0.5;
t=0:0.001:tmax;
fs=1000;
tsamp=0:1/fs:tmax;
f1 = 18;
f2 = 321.37;
y = sin(2*pi*f1*tsamp) + sin(2*pi*f2*tsamp);
figure();
plot(t, y);
grid on;
Y =movmedian(y, 5); % Amplitude
figure
plot(t,Y)
grid on
xlabel('x')
ylabel('|y(x)|')

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