Solving a system with Newton's method in matlab?

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Mery
Mery am 3 Jan. 2023
Bearbeitet: Torsten am 4 Jan. 2023
I have the following system to solve with Newton's method in matlab:
I tried with two variables but I need to solve the system to get the roots a_i and a_j. for i,j=1.2....N (N=1000)
function [a,F,itr] = newtonsys(Ffun,Jfun,a0,B,L,tol ,nmax)
itr= 0; err = tol + 1; a = a0;
while err >= tol & itr< nmax
J =Jfun(a,B,L);
F =Ffun(a,B,L);
delta = - J\F;
a = a + delta;
err = norm(delta,inf);
itr = itr+ 1;
end
return
function F=Ffun(a,B,L)
F(1 ,1) =a(1)*tan(a(1))-B*(1-L*(a(1).^2+a(2).^2));
F(2 ,1) =a(2)*tan(a(2))-B*(1-L*(a(1).^2+a(2).^2));
return
function J=Jfun(a,B,L)
J(1 ,1) =tan(a(1))+a(1)*( tan(a(1)).^2+1); J(1 ,2) = 2*B*L*a(2);
J(2 ,1) =2*B*L*a(1); J(2 ,2) =tan(a(2))+a(2)*( tan(a(2)).^2+1);
return
clc
a0=[10;10]; tol=1e-5; nmax=10000; B=0.1; L=0.1;
[a,F,itr]= newtonsys(@Ffun,@Jfun,a0,B,L,tol,nmax)
I'm a newbie, somebody please help me. thanks a lot advance!
  7 Kommentare
Mery
Mery am 4 Jan. 2023
it is not an exercise, it is one of my projects and I arrived at this (solution , and the roots equation )
the solution:
Torsten
Torsten am 4 Jan. 2023
Bearbeitet: Torsten am 4 Jan. 2023
it is not an exercise, it is one of my projects and I arrived at this (solution , and the roots equation )
Then you must have made a mistake.
As already stated, all alpha_i arbitrary and equal is a solution. And I don't see how you could impose the condition that they should be different for a nonlinear solver.

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