How to remove a part of a character?

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Behrooz Daneshian
Behrooz Daneshian am 3 Jan. 2023
Bearbeitet: Voss am 3 Jan. 2023
Hi all,
Suppose that I have a character called Date='1938-03-01'. I want to remove the year part(1983). 1983 is just an example. I want to remove any year form the date. How can I do that?

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Voss
Voss am 3 Jan. 2023
Bearbeitet: Voss am 3 Jan. 2023
Ran in:
Date = '1938-03-01';
Date(1:4) = []
Date = '-03-01'

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