Plot 2D contour of z at (x,y) coordinates

10 Ansichten (letzte 30 Tage)
Ying Wu
Ying Wu am 29 Dez. 2022
Kommentiert: Voss am 30 Dez. 2022
Hi, I have three arrays with same dimension: xc, rc, P, where xc and yc are coordinates, P is pressure value at (xc,rc). Is there anyway to plot P as a 2D contour?
I know some functions like pcolor(), contourf() can do this thing, but they require P to be a matrix, not an array.
I also know scatter() can do similar thing, but I need a contour (see below), not scattered points. I attach my dataset and the color figure with many scattered points. Thanks for any suggestion!
contour figure (what I want)
scatter figure (what I generate using scatter())
load xc.mat
load rc.mat
load P.mat
scatter(xc,rc,10,P);
axis equal tight, caxis(max(abs(caxis))*[-1 1]);
xlabel('xc'); ylabel('rc');
xlim([0 10]); ylim([0 2]);

Antworten (2)

Walter Roberson
Walter Roberson am 29 Dez. 2022

Voss
Voss am 30 Dez. 2022
load P
load xc
load rc
n_rows = numel(unique(rc));
xcM = reshape(xc,n_rows,[]);
rcM = reshape(rc,n_rows,[]);
PM = reshape(P,n_rows,[]);
contourf(xcM,rcM,PM,'EdgeColor','none')
axis equal tight, caxis(max(abs(caxis))*[-1 1]);
xlabel('xc'); ylabel('rc');
xlim([0 10]); ylim([0 2]);
  2 Kommentare
Ying Wu
Ying Wu am 30 Dez. 2022
@Voss Thanks! But my data is not regular like this (39*175), so I cannot form a coordinate matrix.
Voss
Voss am 30 Dez. 2022
@Ying Wu: Hmm, it seems regular:
load P
load xc
load rc
isequal(rc,repmat(unique(rc),1,175))
ans = logical
1
isequal(xc,repelem(unique(xc),1,39))
ans = logical
1
But regardless, you can use a scatteredInterpolant (which should give the same result in this case, and should work properly if you do have irregular data):
xcd = double(xc);
rcd = double(rc);
I = scatteredInterpolant(xcd(:),rcd(:),P(:));
[xcM,rcM] = ndgrid(unique(xcd),unique(rcd));
contourf(xcM,rcM,I(xcM,rcM),'EdgeColor','none')
axis equal tight, caxis(max(abs(caxis))*[-1 1]);
xlabel('xc'); ylabel('rc');
xlim([0 10]); ylim([0 2]);

Melden Sie sich an, um zu kommentieren.

Tags

Produkte


Version

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by