i have zeros matrix which has 3 rows and 6 columns. i want to allocate “1” on zeros matrix for each columns in order to get the result output like this attached picture. can anyone be kind to help me? thanks in advance

 Akzeptierte Antwort

VBBV
VBBV am 23 Dez. 2022
Bearbeitet: VBBV am 23 Dez. 2022

1 Stimme

As mentioned in your question, if you have zeros matrix to start with and want to allocate 1s to specfiic zero locations, then you can get the matrix in snapshot using loop as below
A = zeros(3,6); % assume A as your zeros matrix
for k = 1:length(A)-2
if k == 1 | k == 2 | k == 3
A(k,k) = 1;
elseif k == 4
A(1,k) = 1;
A(2,k+1) = 1;
A(3,k+2) = 1;
end
end
A
A = 3×6
1 0 0 1 0 0 0 1 0 0 1 0 0 0 1 0 0 1

2 Kommentare

Risma Fitriyani
Risma Fitriyani am 23 Dez. 2022
Thank you for your help, it means a lot to me. Then, what if I have a matrix with a large number of rows and columns like 25x100, should I write it to A(25,k+2)? Or maybe there is a more effective way?
VBBV
VBBV am 23 Dez. 2022
It depends on how you want final matrix to look like. That is "in which specific positions you want to allocate 1s in zero matrix"

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Weitere Antworten (2)

Markus M.
Markus M. am 23 Dez. 2022
Bearbeitet: Markus M. am 23 Dez. 2022

1 Stimme

It looks like the 1's are only needed on the diagonal elements.
You can do this with:
repmat(eye(3),1,2)

4 Kommentare

Risma Fitriyani
Risma Fitriyani am 26 Dez. 2022
how to use that when i have size matrix 15x25?
Markus M.
Markus M. am 26 Dez. 2022
Bearbeitet: Markus M. am 26 Dez. 2022
A more general approach would be:
m = 15;
n = 25;
A = repmat(eye(m),1,ceil(n/m)) %repeat I and store in A.
A = 15×30
1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0
A = A(:,1:n) %cut off last columns from Matrix A
A = 15×25
1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1
m and n define the size of your result.
Note that the repmat command results in a matrix that generally would be too wide ( here ). Therefore you have to cut off the last 5 columns (or take the first n columns of matrix ).
Risma Fitriyani
Risma Fitriyani am 26 Dez. 2022
thank you, i’ll try this
Risma Fitriyani
Risma Fitriyani am 26 Dez. 2022
this is worked! thank you so much, this helped me a lot.

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Image Analyst
Image Analyst am 26 Dez. 2022

1 Stimme

Instead of a for loop, you can use the toeplitz function:
% For 3x6:
c = [1 0 0 1 0 0];
r = [1 0 0];
output = toeplitz(r, c)
output = 3×6
1 0 0 1 0 0 0 1 0 0 1 0 0 0 1 0 0 1
% For 15 by 25
c = [1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1];
r = [1; zeros(15, 1)];
output = toeplitz(r, c)
output = 16×25
1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1 0 0 1

3 Kommentare

Markus M.
Markus M. am 26 Dez. 2022
Didn't think about this interpretation. @Risma Fitriyani can you describe in more detail, what you want your matrix to look like?
Risma Fitriyani
Risma Fitriyani am 26 Dez. 2022
i want the final output would be like the attached picture above (on my question), but i have different various size matrix, that’s why i asked you how if i have size matrix 15x25 because matrix with 3x6 is only example to explain my needs
Image Analyst
Image Analyst am 27 Dez. 2022
@Risma Fitriyani did you not like my answer for the 15x25? Does the answer you accepted work?
Again, can you give the full output for your 15x25 matrix like @Markus M. directly asked you for? I'd like to see how my solution does not do what you want.

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