Antworten (2)

Arif Hoq
Arif Hoq am 6 Dez. 2022
Bearbeitet: Arif Hoq am 6 Dez. 2022

0 Stimmen

x = 1:5;
y = 20:24;
plot(x,y,x(3),y(3),'*') % specify a marker symbol * in index 3 of y
please follow this for more information about plot

3 Kommentare

thank you. How can I mark the point of intersection in the following case?
"
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g')
"
try this approach. I am not sure about his efficiency.
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
[x1equality ia]=find(ismember(t1,t2));
[x3equality ib]=find(ismember(t3,t4));
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g',x1(ia),t1(ia),'*',x3(ib),t3(ib),'*')
Ismita
Ismita am 7 Dez. 2022
Thank you :)

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Walter Roberson
Walter Roberson am 6 Dez. 2022

0 Stimmen

x = 0:0.5:10;
t = (x/2).^2;
abs(x-2*sqrt(t)) %cross-check weether x == 2*sqrt(t)
ans = 1×21
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
plot(x, t, '*-')

5 Kommentare

Ismita
Ismita am 6 Dez. 2022
Bearbeitet: Walter Roberson am 6 Dez. 2022
thank you. How can I mark the point of intersection in the following case? TIA
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g')
You need to calculate the point of interesection between (x2,t2) and (x4,t4) . Then you can plot() that point, specifying a marker. For example,
plot(interesection_x, intersection_y, 'b*')
Ismita
Ismita am 7 Dez. 2022
Problem is, the point of intersection is only one point but the x and t limits are not from the same region (x1, x2, x3, x4 and corresponding t1, t2, t3, t4) plot. The intersection is x4==6.78233, t2==11.66
plot(x4==6.78233, t2==11.66,'r*') does not work
plot(6.78233, 11.66, 'r*')
It does not matter if there is no exact match for this in the curves, if it is the correct intersection point.
Unless, that is, what you want to do is find the closest point on each of the two curves and mark those close points rather than the intersection point?
Ismita
Ismita am 7 Dez. 2022
thank you :)

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