Reverse problem of finding time-varying parameters of an ODE with the help of solution data.

6 Ansichten (letzte 30 Tage)
Any way in which I can find the time-varying parameters of an ODE ; The solution to which is know in the form of time-series data.
Background:
Example: SIR model ode: as following.
% The SIR model differential equations.
def deriv(y, t, beta, gamma):
S, I, R = y
dSdt = -beta * S * I
dIdt = beta * S * I - gamma * I
dRdt = gamma * I
return dSdt, dIdt, dRdt
Then, I use odeint(deriv, y0, t, args=( beta, gamma)) (In python) to solve for S, I and R using minimisation of these parameters.
Question
But I want to ask, is there any way in which a reverse problem can be constructed such that; I have the data for S, I and R as time-sereis. and then we can calculate 'beta' and 'gamma' paramter from there?
Note beta and gamma should be time dependent.They can be assumed as sum of natural cubic splines; Where N_k(t), k=1 to K, are K natural cubic spline basis functions evaluated at K-2 equally spaced knots in addition to the boundary knots .
Can this problem be solved on matlab?
Thanks.
  7 Kommentare
Anshuman
Anshuman am 23 Nov. 2022
Actually I couldn't find a way to implement python packages for this time dependent problem; so I thought of switching to matlab.

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Torsten
Torsten am 23 Nov. 2022
Use "lsqcurvefit" to fit the parameters together with an integrator (e.g. ODE45).
For an example, see Star Strider's code under
Here, four parameters from a Monod Kinetic are fitted against measurement data.
  3 Kommentare
Torsten
Torsten am 23 Nov. 2022
Bearbeitet: Torsten am 23 Nov. 2022
For your first shot, you wanted to estimate the constants a1, b1, a2 and b2, and these are not time-dependent. So the above code can be applied.
For fully time-dependent estimates, look this video to understand how to proceed:

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Eigenvalues & Eigenvectors finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by