Partial derivative with respect to x^2
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Suppose I have a function f
f = (x^5*y^3+ z^2*x^2+y*x) / (x^3*y+x*y)
how do I take derivative of this function with respect to x^2.
I have used diff(f, x^2) but it is returning an error.
syms x y z
f= (x^5*y^3+ z^2*x^2+y*x) / (x^3*y+x*y)
diff(f,x^2)
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Antworten (3)
David Goodmanson
am 18 Nov. 2022
Bearbeitet: David Goodmanson
am 18 Nov. 2022
Hi Yadavindu,
df/d(x^2) = (df/dx) / (d(x^2)/dx) = (df/dx) / (2*x)
which you can code up without the issue you are seeing.
5 Kommentare
David Goodmanson
am 18 Nov. 2022
yes, although you could write it in one line and toss in a simplify:
syms x y z
f= (x^5*y^3+ z^2*x^2+y*x) / (x^3*y+x*y);
f1 = simplify(diff(f,x)/(2*x))
f1 = (2*x^5*y^3 + 4*x^3*y^3 - x^2*z^2 - 2*x*y + z^2)/(2*x*y*(x^2 + 1)^2)
KSSV
am 18 Nov. 2022
syms x y z
f= (x^5*y^3+ z^2*x^2+y*x) / (x^3*y+x*y)
dfdx = diff(f,x)
dfdx2 = diff(dfdx,x)
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