How does the following loop turn out to be different from the expected 25?
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s=0;
I=5;
for i=1:I
for j=1:i
s=s+1
end
end
value(s)
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Walter Roberson
am 18 Nov. 2022
Your inner loop is j=1:i . The first time that is j=1:1 . The second time it is j=1:2 . The third time it is j=1:3, then 1:4, then 1:5 . So the inner loop is going to run 1+2+3+4+5 = 15 times.
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