How to fit lognormal distribution on my data
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    Behrooz Daneshian
 am 15 Nov. 2022
  
    
    
    
    
    Bearbeitet: Jeff Miller
      
 am 18 Nov. 2022
            Hi all,
I have 2 vectors. One is the radious of pores within the soil and other is the number of those pores(frequency). Can anyone help me how I can fit a lognormal distribution to these data?
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  Jeff Miller
      
 am 17 Nov. 2022
        If the scores are in vector1 and the counts are in vector 2, you could fit like this by the method of moments (should be OK with a large dataset):
probs = vector2 / sum(vector2);  % Convert counts to probabilities
ExpOfY = sum(vector1.*probs);   % mean of the scores tabulated in vectors 1 & 2
Ysqr = vector1.^2;
ExpOfYsqr = sum(Ysqr.*probs);
VarOfY = ExpOfYsqr - ExpOfY^2;  % variance of the scores tabulated in vectors 1 & 2
normu = log(ExpOfY/sqrt(1+VarOfY/ExpOfY^2));
norvar = log(1+VarOfY/ExpOfY^2);
norsigma = sqrt(norvar);
dist = makedist('Lognormal','mu',normu,'sigma',norsigma);
x = linspace(0.1,20);  % Use whatever range is appropriate for your data
pdfOfx = pdf(dist,x);
figure; plot(x,pdfOfx);
2 Kommentare
  Jeff Miller
      
 am 17 Nov. 2022
				
      Bearbeitet: Jeff Miller
      
 am 18 Nov. 2022
  
			Part of the problem is that the red and blue curves are scaled differently.  To make them comparable, you need to make them have the same total area under the two curves.  The area under the fitted lognormal is 1, but the area under the red curve is clearly much smaller.  I think need something like:
vector2nor = vector2 / trapz(vector1,vector2);
plot(vector1,vector2nor);
Also, it does not look like the lognormal is actually a very good fit, because the two curves have pretty different shapes (blue descends much more than red across the last 6 tics before 10^-4).
Weitere Antworten (1)
  David Hill
      
      
 am 15 Nov. 2022
        Look at lognfit
[pHat,pCI] = lognfit(repelem(vector1,vector2));
2 Kommentare
  David Hill
      
      
 am 16 Nov. 2022
				if all the frequencies are of the same order of magnitude, you could scale them all down.
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