Input function must return 'double' or 'single' values. Found 'sym'.

9 Ansichten (letzte 30 Tage)
Amitai Sela
Amitai Sela am 15 Nov. 2022
Bearbeitet: Torsten am 15 Nov. 2022
When i use the integral command i get the following error, even though i defined all of the variables:
Error using integralCalc/finalInputChecks
Input function must return 'double' or 'single' values. Found 'sym'.
Error in integralCalc/iterateScalarValued (line 315)
finalInputChecks(x,fx);
.
.
.
Error in int (line 24)
f4 = (1/(t-s^4))*(rho_w_ad+t_w_ad*((x/(t-s))^2-0.5))*exp(-(x/(t-s))^2);
where rho_w_ad, t_w_ad:
syms t s x
alpha = 20;
h = 1;
rho_in = 0;
T_in = exp(-alpha*(s-h));
% this is the first integral
f1 = s*(rho_in*((s^2)/(t^2)-5)+T_in*((s^4)/(t^4)-(11*(s^2))/(2*(t^2))+3.5))*(exp(-s^2/t^2));
firstFunc = matlabFunction(f1);
rho_w_ad = @(t) integral(@(s) firstFunc(s,t) , 0,inf)*(1./t.^2.*(-1./2));
% this is the second integral
f2 = s*(rho_in*((s^2)/(t^2)-1)+T_in*((s^4)/(t^4)-(3*(s^2))/(2*(t^2))+1.5))*(exp(-s^2/t^2));
secondFunc = matlabFunction(f2);
t_w_ad= @(t) integral(@(s) secondFunc(s,t) , 0,inf)*(1./t.^2);
% f4 is further down
what am i doing wrong?

Akzeptierte Antwort

Torsten
Torsten am 15 Nov. 2022
Bearbeitet: Torsten am 15 Nov. 2022
rho_w_ad and t_w_ad are functions of t. So you will have to define
f4 = @(t,x,s) (1./(t-s.^4)).*(rho_w_ad(t)+t_w_ad(t).*((x./(t-s)).^2-0.5)).*exp(-(x./(t-s)).^2);

Weitere Antworten (1)

Marcel
Marcel am 15 Nov. 2022
Bearbeitet: Marcel am 15 Nov. 2022
Have you tried double(yourVarHere) ?
This way you can convert your variable to the expected double and you could try if this fixes your issue. You have to convert the correct variable tho

Kategorien

Mehr zu Programming finden Sie in Help Center und File Exchange

Produkte


Version

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by