Average of array element at defined interval
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Nikhil Chourasia
am 24 Mär. 2015
Beantwortet: prem matlani
am 21 Mär. 2020
Suppose,
a=[1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5]
i want to calculate average of group of five nos. so that my resulting array is like
avg=[3 3 3 3]
Can any one help me for the same.
2 Kommentare
Adam
am 24 Mär. 2015
What does four-four nos. mean? Judging from your example I assume you want the average of groups of 5 numbers. Or do you want 4 averages, irrespective of how many elements fall into the four subsections of your array (whose length may not be divisible by 4)
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Star Strider
am 24 Mär. 2015
Use the rehaspe function, then mean, since it takes the means of columns as its default behaviour:
a=[1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5];
ar = reshape(a, [], 4)
ar_mean = mean(ar)
produces:
ar =
1 1 1 1
2 2 2 2
3 3 3 3
4 4 4 4
5 5 5 5
ar_mean =
3 3 3 3
4 Kommentare
Stelios Fanourakis
am 13 Mai 2019
I think this is what I need. But why I get NaN values when I am using this line
AxesH = set(gca,'XTick',(0.099:1:37.9))
e = double(AxesH)
ar = reshape(e, [], 2)
ar_mean = mean(ar)
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prem matlani
am 21 Mär. 2020

High,
I have collected data from a source and it clearly shows that there has been some tests at specific points in the x axis (1100, 900, 650, 420, 200) approx, how can i filter this data to get rid of the noise within the ranges
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