Test of whether matrix is Symmetric Positive Definite is giving wrong result when matrix is not symmetric
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I'm computing a multivariate normal probability density with an estimated covariance matrix as follows:
% Update the conditional likelihood given the data
p_yk_g_seq_Ykm1(j) = mvnpdf(yk, ykp1_est, Sk);
and getting the following error
Error using mvnpdf (line 127)
SIGMA must be a square, symmetric, positive definite matrix.
Here are some checks I did in the debugger when this error occurred:
K>> Sk
Sk =
0.0540 -0.0001
-0.0001 0.0540
K>> issymmetric(Sk)
ans =
logical
0
Clearly it is not symmetric.
But when I tried to check if Sk is symmetic positive definite using the method described here in the documentaion:
K>> try chol(Sk)
disp('Matrix is symmetric positive definite.')
catch ME
disp('Matrix is not symmetric positive definite')
end
ans =
0.2323 -0.0002
0 0.2323
Matrix is symmetric positive definite.
This confused me. What is going on here? Is it non-symmetric or not PD or both?
Looking in the code for mvnpdf it actually uses this check:
[R,err] = cholcov(Sigma,0);
So maybe the method from the documentation page linked above is wrong or out of date?
Or maybe it tests for positive semi-definite but not symmetric positive semi-definite.
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Weitere Antworten (1)
But when I tried to check if Sk is symmetic positive definite using the method described here in the documentaion:
All of the tests at this link are predicated on the assumption that Sk is already symmetric. In other words, they are really intended as tests of postive or non-negative definiteness, not of symmetry.
Therefore, you should just symmetrize the matrix and be done with it,
Sk=(Sk+Sk.')/2;
This does not change the status of Sk as a PSD or PD matrix.
3 Kommentare
Bill Tubbs
am 9 Nov. 2022
Bill Tubbs
am 9 Nov. 2022
Bruno Luong
am 9 Nov. 2022
Yes all the changes suggested in the doc page are reasonable.
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