Relocate element from a row to another

1 Ansicht (letzte 30 Tage)
Giannakis Stoukas
Giannakis Stoukas am 21 Mär. 2015
Bearbeitet: dpb am 22 Mär. 2015
Hello,i want to relocate an element from a row to an another and delete the other row.For example i have the matrix
A=[1 2 4 8 3 1;
1 9 7 6 1 ;
1 5 1 ]
and i want to relocate the 5 so i will have the matrix
A=[1 2 4 8 3 1;
1 9 7 5 6 1]
  7 Kommentare
the cyclist
the cyclist am 22 Mär. 2015
It's not possible to understand the rule you want to follow, from the one example you give.
Giannakis Stoukas
Giannakis Stoukas am 22 Mär. 2015
Actually it is a problem of local search algorithm,and it is too complicated it explain it from here. I just wanted the orders to move the element 5 between 7 and 6,and move all the other elements one position right.The rule to delete a row is "if the row has only zeros or ones,delete it",and i want the orders to do it.I know i am not very comprehensible,but it is a bit complicated to explain all the theory.

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Antworten (2)

the cyclist
the cyclist am 22 Mär. 2015
A=[1 2 4 8 3 1;
1 9 7 6 1 0;
1 5 1 0 0 0]
A = [A(1,:);
A(2,1:3) A(3,2) A(2,4:5)]
This is my best guess at what you want.

dpb
dpb am 22 Mär. 2015
Bearbeitet: dpb am 22 Mär. 2015
Well, it's not possible to write anything except the specific answer without a definition of the logic. Anything else is indiscernible from magic, not science.
But, let's see, addressing the question as asked...
>> id76=sub2ind(size(A'),4,2);
>> id5=sub2ind(size(A'),2,3);
>> B=reshape(A',1,[]);
>> B=reshape([B(1:id76-1) B(id5) B(id76:id5-1) B(id5+1:end)],size(A,2),[]).';
>> B(all(B==0|B==1,2),:)=[]
B =
1 2 4 8 3 1
1 9 7 5 6 1
>>
Needless to say, to make this of much use in general you'll have to have rules to locate the magic numbers used to compute the indices id5 and id76

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