Getting A blank Graph

trying to graph x against y 1,2 and 3 on same graph , getting blank graph.

for x=0:0.01:1

y1=(0.5*x^5)-(0.6*x^4)-(0.6*x^3)+(0.3*x^2)+0.25;

y2=(sin(x)*cos(x))+(x^2)-1;

y3=(5*x*exp(1)^-5*x)-0.2;

end

plot(x,y1)

hold on

plot(x,y2)

hold on

plot(x,y3)

Answer 1

[Torsten]

I changed y3 to what I think you meant.

x=0:0.01:1;
y1=(0.5*x.^5)-(0.6*x.^4)-(0.6*x.^3)+(0.3*x.^2)+0.25;
y2=(sin(x).*cos(x))+(x.^2)-1;
%y3=(5*x*exp(1)^-5*x)-0.2;
y3 = 5*x.*exp(-5*x)-0.2;

hold on
plot(x,y1,'b')
plot(x,y2,'r')
plot(x,y3,'k')
hold off
grid on

Answer 2

[Davide Masiello]

See below for a correct use of indexing with a for loop

x = 0:0.01:1;
for   i = 1:length(x)
y1(i) = (0.5*x(i)^5)-(0.6*x(i)^4)-(0.6*x(i)^3)+(0.3*x(i)^2)+0.25;
y2(i) = (sin(x(i))*cos(x(i)))+(x(i)^2)-1;
y3(i) = (5*x(i)*exp(1)^-5*x(i))-0.2;
end
figure(1)
plot(x,y1)
hold on
plot(x,y2)
hold on 
plot(x,y3)

Also consider that this can be done in a much more compact way

x = 0:0.01:1;
y1 = (0.5*x.^5)-(0.6*x.^4)-(0.6*x.^3)+(0.3*x.^2)+0.25;
y2 = (sin(x).*cos(x))+(x.^2)-1;
y3 = 5*x.*exp(-5*x)-0.2 % adjusted probable mistake

y3 = 1×101

-0.2000 -0.1524 -0.1095 -0.0709 -0.0363 -0.0053 0.0222 0.0466 0.0681 0.0869 0.1033 0.1173 0.1293 0.1393 0.1476 0.1543 0.1595 0.1633 0.1659 0.1674 0.1679 0.1674 0.1662 0.1641 0.1614 0.1581 0.1543 0.1500 0.1452 0.1401

figure(2)
plot(x,y1,x,y2,x,y3)