May I ask how I can find 95% confidence interval of skew_FP() from these codes?

1 Ansicht (letzte 30 Tage)
rng(1000)
nn=143;
for n=1:1000;
r=rand(nn,1);
ss(n)=std(r);
m(n)=mean(r);
med(n)=median(r);
nu(n)=numel(r)
skew_FP(n) = sum((r-m(n)).^3)/(nn-1)/ss(n).^3
end
hist(skew_FP())
xlabel('Skew_FP()')
ylabel('Frequency')

Akzeptierte Antwort

Jeff Miller
Jeff Miller am 30 Okt. 2022
LBUB = prctile(skew_FP(),[2.5,97.5]);

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