How to merge matrix in a loop?

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Akshay Sahu
Akshay Sahu am 28 Okt. 2022
Kommentiert: Akshay Sahu am 29 Okt. 2022
Suppose I have four matrix
A,B,C and D. These all are (mx3) matrix where m is some number.
and I have to define a number as an user input which is N.
Now I want a merge matrix such that,
for N = 1
New_matrix = [A]
for N = 2
New_matrix = [A
B
C]
for N = 3
New_matrix = [A
B
C
D
A]
for N = 4
New_matrix = [A
B
C
D
A
B
C]
and so on......

Akzeptierte Antwort

David Hill
David Hill am 28 Okt. 2022
A=randi(10,4,3)
A = 4×3
10 2 9 7 7 4 10 5 1 5 9 2
B=randi(10,5,3)
B = 5×3
8 6 1 10 1 9 6 5 9 5 8 8 10 3 3
C=randi(10,6,3)
C = 6×3
1 6 4 9 4 2 7 5 6 9 5 4 3 2 5 1 2 7
D=randi(10,7,3)
D = 7×3
5 8 3 4 9 5 5 3 9 6 7 7 4 9 3 8 5 6 7 9 9
N=2;
newMatrix=generateMatrix(A,B,C,D,N)
newMatrix = 15×3
10 2 9 7 7 4 10 5 1 5 9 2 8 6 1 10 1 9 6 5 9 5 8 8 10 3 3 1 6 4
function newMatrix=generateMatrix(A,B,C,D,N)
n=2*N-1;
s=[size(A,1),size(B,1),size(C,1),size(D,1)];
newMatrix=repmat([A;B;C;D],ceil(n/4),1);
S=sum(s*floor(n/4))+sum(s(1:mod(n,4)));
newMatrix=newMatrix(1:S,:);
end
  1 Kommentar
Akshay Sahu
Akshay Sahu am 29 Okt. 2022
Thank you @David Hill, your algorithm worked as I want.

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KALYAN ACHARJYA
KALYAN ACHARJYA am 28 Okt. 2022
Bearbeitet: KALYAN ACHARJYA am 28 Okt. 2022
% Just example
A=rand(4,3);
B=rand(4,3);
C=rand(4,3);
D=rand(4,3);
data_mat={A,B,C,D}; % Created to handle data easily
N=4 ; % Example or length of data_mat
data=cell(1,N); %Memory Pre-allocation
for i=1:N
data{i}=horzcat(data_mat{1:i});
end
data
data = 1×4 cell array
{4×3 double} {4×6 double} {4×9 double} {4×12 double}
You may look for cellfun also, please do the modification as per requirements.
  2 Kommentare
KALYAN ACHARJYA
KALYAN ACHARJYA am 28 Okt. 2022
To store matrix or any other data type, cell array is much easier way to handle it.
Hope it helps!
Akshay Sahu
Akshay Sahu am 29 Okt. 2022
Yes, It's also correct for N=4. But N is not constant in my case. I want to change value of N according to my need.

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