Hello Experts,
Consider I have to sum from i=1 to 2^(n-1) (n is given) values of some function f(i).
How can I do it like series in math sum from i=1 to 2^(n-1) of f(i)...
Thanks a lot in advance.

 Akzeptierte Antwort

Naz
Naz am 15 Okt. 2011

1 Stimme

n=given;
i=1:2^(n-1); %gives you array of integers from 1,2,...2^(n-1)
% let's say your function is f=2i;
f=2*i;
yoursum=sum(f);

2 Kommentare

Steve
Steve am 15 Okt. 2011
Function f is transferred as anonymous one to my function.
What should I change?
Walter Roberson
Walter Roberson am 15 Okt. 2011
n=given;
fsum = 0;
for i=1:2^(n-1)
fsum = fsum + f(i);
end

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