Question about to reconduct [for loop statement] to the code using vectorization

1 Ansicht (letzte 30 Tage)
hello
first i made the code that he answer to the following expression is 0.7849
its expression is
the code i made is (result is 0.7849)
sum=0;
for m=0:2:10000000
k=m;
i=m+1;
sumx=(1/(2*k+1));
sumy=(-1/(2*i+1));
sum=sumx+sumy+sum
end
-----------------------------------------------------------------------------------------------
So, What I want to do is to reconstruct the code above using vectorization.(use ./ .*) (not using for loop statement)
i made this, but it works strangely.(I don't know if I made it right)
format short
sum=0;
m=0:2:500;
k=m;
i=m+1;
sumx=(1./(2*k+1));
sumy=(-1./(2*i+1));
sum=sumx+sumy+sum
Should I write more variable?
How do I reconstruct it right?
  2 Kommentare
VBBV
VBBV am 26 Okt. 2022
format short
sumi=0; % sum is builtin function of matlab
m=0:2:500;
k=m;
i=m+1;
sumx=sum((1./(2*k+1))); % apply the sum function to the series
sumy=sum((-1./(2*i+1))); % sum the series
Sum=sumx+sumy+sumi
Sum = 0.7849
sum is a builtin function in matlab, variables are usually named that doesnt conflict with standard builtin functions in matlab,
N/A
N/A am 26 Okt. 2022
Bearbeitet: N/A am 26 Okt. 2022
i did simillar as you did, but it didnt work because i used 'sum' function as it.
after seeing this, i found my fault.
thanks!

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

David Hill
David Hill am 26 Okt. 2022
format long
s=sum(1./(2*(0:2:500)+1)-1./(2*(1:2:501)+1))
s =
0.784900155923366

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Produkte


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by