Plotting discontinuous discrete signal with shift and fold
31 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello !
I have a given question below
x[n]= {1+n/3 -3<=n<=-1,
1 0<=n<=3,
0 other wise}
I have to plot this signal and I have developed the following code for that
clc
n=-10:1:10;
for i=1:length(n)
if n(i)>=-3 && n(i)<=-1
x(i)=1+(n(i)/3);
elseif n(i)>=1 && n(i)<=3
x(i)=1;
else
x(i)=0;
end
stem(x)
end
axis([-20 20 0 2])
but the resulting waveform is plotted for positive values of n, Kindly help me to plot the above sequence,
0 Kommentare
Antworten (4)
Gnaneswar Nadh satapathi
am 6 Nov. 2013
clc clear all close all n=-10:1:10; for i=1:length(n) if n(i)>=-3 && n(i)<=-1 x(i)=1+(n(i)/3); elseif n(i)>=1 && n(i)<=3 x(i)=1; else x(i)=0; end
end stem(n,x)
1 Kommentar
Sk Group
am 8 Feb. 2021
MATLAB CODE:
function [n1,x1] = sigshift(x,n,k)
n = 1:10;
k = 2;
x = exp(n);
if k>0
disp(‘Positive’);
n1 = n(1):n(end)+k;
x1 = [zeros(1,k) x];
else
disp(‘Negative’);
n1 = n(1)+k:n(end);
x1 = [x zeros(1,abs(k))]; % abs is for absolute value of (k) because quantity can never be (-ve) negative %
end
MATLAB CODE:
function [y n1] = sigfold(x,n)
n1 = -fliplr(n)
y = fliplr(x)
end
1 Kommentar
Siehe auch
Kategorien
Mehr zu Graphics Performance finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!