Not sure how to continue/finish this problem

function [n, precision, y] = MyCos(tolerance, N, x)
SUM = 0;
for n = 0:N
    SUM = SUM + (-1)^n*(x^2*n)/factorial(2*n);

end

I don't think I need the SUM. I think I should replace it with cos(x), but not sure. Not sure where it would go after that. Please include an explanation if possible.

Thank you

[Rena Berman]

(Answers Dev) Restored edit

Answer 1

[Walter Roberson]

No, you do need the sum.

The task is

initialize variables
start a for loop
  generate the next term
  if the absolute value of the term is less than the tolerance then break
  otherwise add the term to sum 

   after the for loop, also call cos() and report how close the estimate was to the actual value