How to use a 'for loop' with inputs from the output of a previous equation.

2 Ansichten (letzte 30 Tage)
Hello, Below is the code for inverse kinematics of a robot.
I wish to use the output of Theta [2x1] in for loop where value in first row and first colums of Theta is used in first iteration and value in 1st row and second column is used in second iteration.
I am new to Matlab.
gd=[-0.0256,-0.4496,-0.8929,-4.197;0.9758,0.1829,-0.1200,15.369;0.2173,-0.8743,0.4340,13.931;0,0,0,1];
gst0=[1 0 0 33; 0 1 0 -13; 0 0 1 14.7; 0 0 0 1];
g1=gd*inv(gst0);
p1=[24;-13;14.7];
p2=[0;-13;14.7];
r=[12;-13;0];
Delta=norm((g1*[p1;1])-[p2;1])
w4=[0;0;-1];
w=w4;
p=p1;
q=p2;
Theta=Thirdsubproblem (w,Delta,p,q,r)
for i=Theta(1,1):Theta(1:2)
w5=[0;0;-1];
w6=[1;0;0];
I=[1,0,0;0,1,0;0,0,1];
q4=[12;-13;14.7];
expOmega4hatTheta4=[cos(i),-sin(i),0;sin(i),cos(i),0;0,0,1];
expPsihat4Theta4=[expOmega4hatTheta4,((I-expOmega4hatTheta4)*q4);0,0,0,1];
p2=[0;-13;14.7];
p3=expPsihat4Theta4*[p2;1];
gd=[-0.0256,-0.4496,-0.8929,-4.197;0.9758,0.1829,-0.1200,15.369;0.2173,-0.8743,0.4340,13.931;0,0,0,1];
gst0=[1 0 0 33; 0 1 0 -13; 0 0 1 14.7; 0 0 0 1];
g2p2=inv(gd)*gst0*[p2;1];
q=p3([1,2,3],:);
p=g2p2([1,2,3],:);
w1=w5;
w2=w6;
r=[24;-13;14.7];
[Gamma]=Secondsubproblem (w1,w2,p,q,r)
for X=Gamma(1,1):Gamma(1:2)
u=p-r;
v=q-r;
alpha=((w1'*w2)*w2'*u-w1'*v)/(((w1'*w2)^2)-1);
Beta=((w1'*w2)*w1'*v-w2'*u)/(((w1'*w2)^2)-1);
z=(alpha*w1)+(Beta*w2)+(X)*(cross(w1,w2));
c=z+r;
Theta2SP2=Firstsubproblemsecond1 (w2,p,z,r)
Theta1SP1=Firstsubproblemsecond2 (w1,q,z,r)
clear
end
clear
end

Akzeptierte Antwort

Ghazwan
Ghazwan am 15 Okt. 2022
gd=[-0.0256,-0.4496,-0.8929,-4.197;0.9758,0.1829,-0.1200,15.369;0.2173,-0.8743,0.4340,13.931;0,0,0,1];
gst0=[1 0 0 33; 0 1 0 -13; 0 0 1 14.7; 0 0 0 1];
g1=gd*inv(gst0);
p1=[24;-13;14.7];
p2=[0;-13;14.7];
r=[12;-13;0];
Delta=norm((g1*[p1;1])-[p2;1])
w4=[0;0;-1];
w=w4;
p=p1;
q=p2;
Theta=Thirdsubproblem(w,Delta,p,q,r)
for ii=1:2
i=Theta(1,ii);
w5=[0;0;-1];
w6=[1;0;0];
I=[1,0,0;0,1,0;0,0,1];
q4=[12;-13;14.7];
expOmega4hatTheta4=[cos(i),-sin(i),0;sin(i),cos(i),0;0,0,1];
expPsihat4Theta4=[expOmega4hatTheta4,((I-expOmega4hatTheta4)*q4);0,0,0,1];
p2=[0;-13;14.7];
p3=expPsihat4Theta4*[p2;1];
gd=[-0.0256,-0.4496,-0.8929,-4.197;0.9758,0.1829,-0.1200,15.369;0.2173,-0.8743,0.4340,13.931;0,0,0,1];
gst0=[1 0 0 33; 0 1 0 -13; 0 0 1 14.7; 0 0 0 1];
g2p2=inv(gd)*gst0*[p2;1];
q=p3([1,2,3],:);
p=g2p2([1,2,3],:);
w1=w5;
w2=w6;
r=[24;-13;14.7];
[Gamma]=Secondsubproblem (w1,w2,p,q,r)
for jj=1:2
X=Gamma(1,jj);
u=p-r;
v=q-r;
alpha=((w1'*w2)*w2'*u-w1'*v)/(((w1'*w2)^2)-1);
Beta=((w1'*w2)*w1'*v-w2'*u)/(((w1'*w2)^2)-1);
z=(alpha*w1)+(Beta*w2)+(X)*(cross(w1,w2));
c=z+r;
Theta2SP2=Firstsubproblemsecond1 (w2,p,z,r)
Theta1SP1=Firstsubproblemsecond2 (w1,q,z,r)
clear
end
clear
end

Weitere Antworten (0)

Kategorien

Mehr zu Language Fundamentals finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by