Plotting (1-2*x)*log((1-x)/x)

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kemal sen
kemal sen am 8 Mär. 2015
Kommentiert: Walter Roberson am 16 Nov. 2020
Hello!. I am very new to matlab and wanna know how can I plot
y=(1-2*x)*log((1-x)/x) function?
I tried to write it like that but it did not work as i expected.. It plots something else..
thanks..
and also why i cannot plot (1/x)? thanks.
  2 Kommentare
Geoff Hayes
Geoff Hayes am 8 Mär. 2015
Kemal - what is the code that you are using to plot your above y? What have you initialized x as?
kemal sen
kemal sen am 8 Mär. 2015
Bearbeitet: Walter Roberson am 16 Nov. 2020
I used this
x=0:0.2:1;
y=(1-2*x)*log((1-x)/x) ;
plot(x,y)

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Antworten (2)

Giorgos Papakonstantinou
Giorgos Papakonstantinou am 8 Mär. 2015
Bearbeitet: Giorgos Papakonstantinou am 8 Mär. 2015
The problem occurs inside the log parenthesis. The syntax that you have used tells Matlab to solve the equation:
x = B/A
for x. Check the documentation for mrdivide to get more a thorough explanation.
If you want to do element-wise arithmetic operations (division, power, etc.) then you have to use . before each operation. Look for more information here.
In your case you have to modify your equation:
y=(1-2.*x).*log((1-x)./x)
Here the log function computes the natural logarithm.
or
y=(1-2.*x).*log10((1-x)./x)
Here the log10 function computes the logarithm when the base is 10
For example if:
x=0:0.02:1;
y=(1-2*x).*log((1-x)./x) ;
plot(x,y)
the result is:
  1 Kommentar
kemal sen
kemal sen am 8 Mär. 2015
Bearbeitet: kemal sen am 8 Mär. 2015
Thank you very much..

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D tk
D tk am 16 Nov. 2020
plot y=0.5*ln(pi*e),e is exp^1

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