How to solve 2nd ODE equation in numerical and analytical method at same plot graph?

8 Ansichten (letzte 30 Tage)
Hello,
I am was looking for help to solve this equation
a. dx/dt = -x
b. dx/dt = -x+1
in Matlab, can I get help to solve this equation of plot the numerical solutions and analytical solutions in the same graph and compare them.
with ode45
can anyone help me with this code?
  6 Kommentare
Shreyas Sangamesh
Shreyas Sangamesh am 28 Sep. 2022
Its not the same one I asked before,
I just wanted to have some assistance on how these equation behave in 1st order ODE,
I have got the revelant idea on how to carry it out!!
Thank you
Torsten
Torsten am 28 Sep. 2022
Bearbeitet: Torsten am 28 Sep. 2022
a .
dx/dt = - x -> dx/x = -dt -> log(x/x0) = (t0-t) -> x = x0 * exp(t0-t)
b.
dx/dt = -x+1 -> dx/(x-1) = -dt -> log((x-1)/(x0-1)) = t0-t -> x-1 = (x0-1)*exp(t0-t) -> x = 1 + (x0-1)*exp(t0-t)

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Sai
Sai am 12 Okt. 2022
I understand that you are trying to solve the differential equations both numerically and analytically and get the plots on same graph for comparison.
You can use available MATLAB functions “ode45” for numerical approach and “dsolve” for analytical approach.
Please refer to the attached code snippets, which can help you solve the problem.
NOTE: Since the initial conditions are not given, they are assumed
a). dx/dt = -x
%Numerical Method
[t,x] = ode45(@(t,x) -x,[0 20],1)
plot(t,x)
hold on
%Analytical Method
syms x(t)
dx = diff(x)
eqn = dx==-x
x(t) = dsolve(eqn,x(0)==1)
t = 0:20
plot(t,x(t))
hold off
legend("Numerical","Analytical")
b). dx/dt = -x+1
%Numerical Method
[t,x] = ode45(@(t,x) -x+1,[0 20],0)
plot(t,x)
hold on
%Analytical Method
syms x(t)
dx = diff(x)
eqn = dx==-x+1
x(t) = dsolve(eqn,x(0)==0)
t = 0:20
plot(t,x(t))
hold off
legend("Numerical","Analytical")
You can also refer to the below links regarding “ode45” and “dsolve” for future references.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by